The Jacobi-Madden soln to a^4+b^4+c^4+d^4 = e^4 and Pythagorean triples
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Nieuwsgroepen: sci.math, alt.math.recreational
Van:
TPiezas <tpie... @gmail.com>
Datum: Tue, 9 Feb 2010 01:21:21 -0800 (PST)
Lokaal: di 9 feb 2010 10:21
Onderwerp: The Jacobi-Madden soln to a^4+b^4+c^4+d^4 = e^4 and Pythagorean triples
Hello all, L. Jacobi and D. Madden proved that a^4+b^4+c^4+d^4 = e^4 has an infinite number of distinct, non-trivial rational solns by solving the case,
a^4+b^4+c^4+d^4 = (a+b+c+d)^4
which is just a special Pythagorean triple in disguise, namely,
(a^2+ab+b^2)^2 + (c^2+cd+d^2)^2 = ((a+b)^2+(a+b)(c+d)+(c+d)^2)^2
For details on how they solved this triple, see http://sites.google.com/site/tpiezas/updates02 .
- Titus
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Nieuwsgroepen: sci.math, alt.math.recreational
Van:
Pubkeybreaker <pubkeybrea... @aol.com>
Datum: Tue, 9 Feb 2010 03:08:21 -0800 (PST)
Lokaal: di 9 feb 2010 12:08
Onderwerp: Re: The Jacobi-Madden soln to a^4+b^4+c^4+d^4 = e^4 and Pythagorean triples
On Feb 9, 4:21 am, TPiezas <tpie... @gmail.com> wrote:
> Hello all,
> L. Jacobi and D. Madden proved that a^4+b^4+c^4+d^4 = e^4 has an > infinite number of distinct, non-trivial rational solns by solving the > case,
> a^4+b^4+c^4+d^4 = (a+b+c+d)^4
> which is just a special Pythagorean triple in disguise, namely,
> (a^2+ab+b^2)^2 + (c^2+cd+d^2)^2 = ((a+b)^2+(a+b)(c+d)+(c+d)^2)^2
> For details on how they solved this triple, seehttp://sites.google.com/site/tpiezas/updates02 .
> - Titus
So? This is nothing new. Elkies proved that one may always take d=0. i.e. a^4+b^4+c^4 = e^4 has infinitely many integer solutions.
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Van:
Frederick Williams <frederick.willia... @tesco.net>
Datum: Tue, 09 Feb 2010 12:29:01 +0000
Lokaal: di 9 feb 2010 13:29
Onderwerp: Re: The Jacobi-Madden soln to a^4+b^4+c^4+d^4 = e^4 and Pythagorean triples
Pubkeybreaker wrote:
> On Feb 9, 4:21 am, TPiezas <tpie... @gmail.com> wrote: > > Hello all,
> > L. Jacobi and D. Madden proved that a^4+b^4+c^4+d^4 = e^4 has an > > infinite number of distinct, non-trivial rational solns by solving the > > case,
> > a^4+b^4+c^4+d^4 = (a+b+c+d)^4
> > which is just a special Pythagorean triple in disguise, namely,
> > (a^2+ab+b^2)^2 + (c^2+cd+d^2)^2 = ((a+b)^2+(a+b)(c+d)+(c+d)^2)^2
> > For details on how they solved this triple, seehttp://sites.google.com/site/tpiezas/updates02 .
> > - Titus
> So? This is nothing new. Elkies proved that one may always take > d=0. i.e. > a^4+b^4+c^4 = e^4 has infinitely many integer solutions.
Maybe non-trivial excludes 0. -- ... A lamprophyre containing small phenocrysts of olivine and augite, and usually also biotite or an amphibole, in a glassy groundmass containing analcime.
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