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Newsgroups: comp.dsp, alt.engineering.electrical, sci.math, uk.radio.amateur
From: Han de Bruijn <Han.deBru...@DTO.TUDelft.NL>
Date: Fri, 10 Dec 2004 16:30:14 +0100
Local: Fri, Dec 10 2004 4:30 pm
Subject: Re: Disappointed
David C. Ullrich wrote: I hope you understand that the document is taylored to Mr. Bean. > if you do that then the Laplace transform comes out to exactly > what it does using the much simpler argument from the > actual standard definition of delta. > In case you're curious, there's a standard way to prove what As a matter of fact, I'm curious ... > you prove in that pdf, which is both simpler and much more > powerful. Let's say g_sigma(t-T) is that gaussian function. > The result follows immediately from the following three OK, until now. > properties of g_sigma (the proof is more powerful because > it works for _any_ family of functions satisfying these > three properties): > (i) g_sigma >= 0. > (ii) int g_sigma = 1. > (iii) If a > - is fixed then What does 'a > -' mean? And what is 's'? > int_{|t-T| > a} g_sigma(t-T) dt -> 0 as s -> 0. Han de Bruijn You must Sign in before you can post messages.
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